util: Use 'long' to represent millisecond durations

timespec_diff_ms() returns an int representing a duration in milliseconds.
This will overflow in about 25 days when an int is 32 bits.  The way we
use this function, we're probably not going to get a result that long, but
it's not outrageously implausible.  Use a long for safety.

Signed-off-by: David Gibson <david@gibson.dropbear.id.au>
Signed-off-by: Stefano Brivio <sbrivio@redhat.com>

1 files changed, 1 insertions, 1 deletions

diff --git a/util.c b/util.c
index 5e854a2..4446180 100644
--- a/util.c
+++ b/util.c
@@ -216,7 +216,7 @@ void sock_probe_mem(struct ctx *c)
  *
  * Return: difference in milliseconds
  */
-int timespec_diff_ms(const struct timespec *a, const struct timespec *b)
+long timespec_diff_ms(const struct timespec *a, const struct timespec *b)
 {
 	if (a->tv_nsec < b->tv_nsec) {
 		return (b->tv_nsec - a->tv_nsec) / 1000000 +