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author | David Gibson <david@gibson.dropbear.id.au> | 2024-06-06 20:09:49 +1000 |
---|---|---|
committer | Stefano Brivio <sbrivio@redhat.com> | 2024-06-07 20:44:44 +0200 |
commit | 3f63743a65bf3d987615774cdab0a9cb1006ae47 (patch) | |
tree | 73f480fecfb74885b272eb9a6c0806ae0566e044 | |
parent | f9e8ee0777c257ffd2956a6dd51e866dff26bc8e (diff) | |
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util: Use 'long' to represent millisecond durations
timespec_diff_ms() returns an int representing a duration in milliseconds.
This will overflow in about 25 days when an int is 32 bits. The way we
use this function, we're probably not going to get a result that long, but
it's not outrageously implausible. Use a long for safety.
Signed-off-by: David Gibson <david@gibson.dropbear.id.au>
Signed-off-by: Stefano Brivio <sbrivio@redhat.com>
-rw-r--r-- | util.c | 2 | ||||
-rw-r--r-- | util.h | 2 |
2 files changed, 2 insertions, 2 deletions
@@ -216,7 +216,7 @@ void sock_probe_mem(struct ctx *c) * * Return: difference in milliseconds */ -int timespec_diff_ms(const struct timespec *a, const struct timespec *b) +long timespec_diff_ms(const struct timespec *a, const struct timespec *b) { if (a->tv_nsec < b->tv_nsec) { return (b->tv_nsec - a->tv_nsec) / 1000000 + @@ -147,7 +147,7 @@ int sock_l4(const struct ctx *c, sa_family_t af, uint8_t proto, const void *bind_addr, const char *ifname, uint16_t port, uint32_t data); void sock_probe_mem(struct ctx *c); -int timespec_diff_ms(const struct timespec *a, const struct timespec *b); +long timespec_diff_ms(const struct timespec *a, const struct timespec *b); void bitmap_set(uint8_t *map, unsigned bit); void bitmap_clear(uint8_t *map, unsigned bit); bool bitmap_isset(const uint8_t *map, unsigned bit); |